Electric Flux Density for Coaxial Cable

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Homework Statement



I am given the following problem:
[URL]http://forum.allaboutcircuits.com/attachment.php?attachmentid=35938&d=1320027350[/URL]

Homework Equations


The Attempt at a Solution



My known equations and attempt to the problem:

[URL]http://forum.allaboutcircuits.com/attachment.php?attachmentid=35940&stc=1&d=1320028178[/URL]

Basically, my answer to the problem is not the same as the book's answer, and I'm pretty sure I'm using the right equations. What could I possibly be doing wrong here? I've been trying to figure this out for three hours now, and am now frustrated. I apologize for my ignorance here, but any advice or tips will be greatly appreciated.
 
Last edited by a moderator:
Sorry about that. This should work now,

Homework Statement



I am given the following problem:

Figure P3.2: side view and front view of a coaxial power cable, with labelled radii a, r1, r2 and r3, permittivities e1 and e2 in the two regions, and a voltage source V connected to the inner conductor.


Homework Equations


3. The Attempt at a Solution [/B]

My known equations and attempt to the problem:

Handwritten-style typeset derivation listing D = e0 er E, E = Q/(4 pi e0 R^2) a_r and P = e0 Xe E, then a worked attempt for the region a < rho < r1 with dielectric e1 = 1.5 e0, giving D and E results compared against the book's answers.


Basically, my answer to the problem is not the same as the book's answer, and I'm pretty sure I'm using the right equations. What could I possibly be doing wrong here? I've been trying to figure this out for three hours now, and am now frustrated. I apologize for my ignorance here, but any advice or tips will be greatly appreciated.
 
Attachments
  • Figure P3.2 from a textbook: side view and front view of a coaxial power cable, with labels a, r1, r2, r3, permittivities e1 and e2, and a voltage source V on the side view.
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  • Handwritten-style typed working listing electric flux density D = epsilon_0 epsilon_r E, field E = Q over 4 pi epsilon_0 R^2 a_r, and polarization P = epsilon_0 X_e E, followed by two region attempts comparing the student's expressions with the book's answers.
    Screen Shot 2011-10-30 at 4.28.31 PM.png
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Since D is radial, have you tried:

[tex]\frac{1}{r}\frac{d}{dr}r{\bf D} = \rho_{free}[/tex]

... for the appropriate boundary conditions?

(aside: Don't you hate it when people duplicate constant and variable symbols - try [itex]\rho[/itex]=r, r1=b and r2=c, ... this allows you to keep [itex]\rho[/itex] values for densities: it'll make discussions easier.)

You will certainly not get an inverse-square relationship as that only happens for spherical symmetry.
Your problem has cylindrical symmetry.
 
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I don’t see this equation in my book, but I tried it.

Handwritten-style typed derivation: region a < ρ < b with ε1 = 1.5 ε0, D = ε0εr E = ε0(1.5ε0)E, and boundary condition (1/r) d/dr (rD) = ρfree, written as (1/r) d/dr r[ε0(1.5ε0)E] = ρ.


I'm not sure where to go from here. Is my equation for E correct?

Could someone please provide me with an example to get me going. My assignment is due very soon and any help is greatly greatly appreciated.

Thank you!
 
Attachments
  • Handwritten-style typed derivation for a coaxial cable dielectric: rho = r, r1 = b, r2 = c; region a < rho < b with epsilon 1 = 1.5 epsilon 0; D = epsilon 0 epsilon r E = epsilon 0 (1.5 epsilon 0)E; boundary condition (1/r) d/dr r D = rho free, written as (1/r) d/dr r[epsilon 0 (1.5 epsilon 0)E] = rho.
    Screen Shot 2011-11-05 at 5.50.51 PM.png
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Google for "electric field cylindrical capacitor" - there's lots.

Using D:
You have to solve the differential equation in general, this will give you some "arbitrary constants" that you find values for from the boundary conditions for each region.

On the inner core surface, you have a charge distribution ... you have a balancing charge distribution on the outer surface, the electric field outside the cable is zero. The D field has to be continuous across all the regeons and you need to know the relationship between D and E.

The equation I gave you was just [itex]\nabla {\bf D} = \rho_{free}[/itex] for cylindrical co-ordinates.

(Note: from gausses law, the field between a and c without the dielectric would be the same as that due to a line of charge right down the middle.)