- #1

mandos

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**Homework Statement**

(Prior to start of questions, it informs me the relative permittivity of free space is 8.9x10^-12)

2) An alpha particle (charge 3.2x10^-19) approaches to a distance of 1.5x10^-17 from a gold nucleus (charge 1.3x10^-17). Calculate:

a) the strength of the field created by the gold nucleus at the distance of the alpha particles closest approach.

**2. Homework Equations + Attempt at a solution**

According the back of the book, the answer is 5.2 x 10^22 Vm^-1

Because it gave me the relative permittivity of free space, I tried using that (even though it could be for other questions, like question 1, where I needed it).

So I used F= Q1,Q1 / 4xPiex8.9x10^-12xr^2

Where I used the two charges provided and I used the distance as the radius (r).

That didn't work.

So I assumed that due to the units the back of the book gives (Vm^-1), the right equation to use would be V= Ed. But, if I rearrange is to get E .. I don't have the value of V.

But I do still think that V = Ed is barking up the right tree. But how do I find V? W = VQ? But how do I know W?

The problem is, I can't think of any other equations that are suitable to use, apart from the above two that I've discussed.

Any help would be much appreciated.