The problem statement, all variables and given/known data (Prior to start of questions, it informs me the relative permittivity of free space is 8.9x10^-12) 2) An alpha particle (charge 3.2x10^-19) approaches to a distance of 1.5x10^-17 from a gold nucleus (charge 1.3x10^-17). Calculate: a) the strength of the field created by the gold nucleus at the distance of the alpha particles closest approach. 2. Relevant equations + Attempt at a solution According the back of the book, the answer is 5.2 x 10^22 Vm^-1 Because it gave me the relative permittivity of free space, I tried using that (even though it could be for other questions, like question 1, where I needed it). So I used F= Q1,Q1 / 4xPiex8.9x10^-12xr^2 Where I used the two charges provided and I used the distance as the radius (r). That didn't work. So I assumed that due to the units the back of the book gives (Vm^-1), the right equation to use would be V= Ed. But, if I rearrange is to get E .. I don't have the value of V. But I do still think that V = Ed is barking up the right tree. But how do I find V? W = VQ? But how do I know W? The problem is, I can't think of any other equations that are suitable to use, apart from the above two that I've discussed. Any help would be much appreciated.