Calculating Potential Difference in a Teltron Tube

AI Thread Summary
The discussion centers on calculating the potential difference in a Teltron tube when 3000V is applied. It is suggested that the potential difference between the parallel plates would be 6000V, considering one plate is positive and the other negative. The conversation highlights the importance of understanding the voltage configuration, especially in devices requiring balanced positive and negative voltages. Additionally, clarification is sought on the specific connections and labeling of the sockets in the experimental setup to ensure accurate calculations. Understanding the setup and voltage requirements is crucial for determining the potential difference in this context.
LXX
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Homework Statement


If 3000V is applied to the teltron tube with EHT voltage, what would be the potential difference between the parallel plates in the teltron tube?

Homework Equations

The Attempt at a Solution


Since one end of the plate is positive, the other end is negative, 3000V-(-3000V)=6000V
 
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I don't know a teltron tube, but in general if you supply a device with 3000v then the cables carry a potential difference of 3000v. If there are two cables, one will be 3000v more than the other. For devices which need balanced + and - voltages this fact is usually made abundantly clear, e.g., requires ±3000v, and it will need 3 power cables with one of them being ground (i.e., 0v) to which the other potentials are referenced.

If a teltron tube is something peculiar, please indicate this and include a link to it to assist respondants to your thread.
 
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You'll need to sketch the experimental set-up; we've no way of knowing which plates you're discussing.
 
Below is the experiment set up. Thank you
 

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The electron beam travels thru the gap between parallel plates, supplied by the
(Tel-Atomic?) PS on the left. Bottom plate connection appears to be red (+) socket.
Not clear what color socket Top plate is connected to ... below the meter, left side ... it SHOULD be labeled.
if it is black, then (almost guarantee) it is ground (0).

(Peculiar to use a deflection voltage that high, but the plates ARE far apart ...)
 
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