Electric Potential Homework: E=-20x+12; x=0.6m

AI Thread Summary
The electric potential is given by V = 10x^2 - 12x + 63, and the electric field is calculated using the derivative formula E = -dV/dx. The derivative yields E = -20x + 12, resulting in an electric field of -48 V/m when x = 3m. To find where the electric field is zero, setting E to zero gives x = 0.6m. The calculations and approach used to solve the problem are confirmed to be correct.
kiwikahuna
Messages
60
Reaction score
0

Homework Statement


The electric potential in a certain region is
V = 10x^2 -12x + 63
Determine the electric field at x = 3m. Answer in units of V/m.
Determine the position where the electric field is zero. Answer in units of m.

Homework Equations


E = -(partial derivative V / partial derivative X)



The Attempt at a Solution


I took the derivative of V : V' = 20x -12
E = -20x + 12
I plugged in 3 for x and found that the electric field is -48 V/m.
To find the second part of this problem, I used the same equation and set E = 0. I found x to be 0.6 m.

Is this the right way to work this problem? Thanks.
 
Physics news on Phys.org
Looks good. Nice Job!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top