Electricity-Resistance Question

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To achieve a voltage drop of 5.0V with a total current of 2.0mA, the effective resistance required is 2,500 Ohms. The student can use a 4.0kOhm resistor in parallel with a second resistor to meet this requirement. The value for the second resistor should be approximately 6.7 kOhms to achieve the desired effective resistance. The formula for calculating the equivalent resistance in parallel is R_eq = R1*R2/(R1+R2). Understanding these calculations is essential for constructing the circuit correctly.
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Homework Statement



A Student needs to construct a circuit in which there is a voltage drop of 5.0v across a resistance combination, and a total current of 2.0mA flowing through the combination. She has a 4000 Ohm ( 4.0kOhm) resistor which she wants to use and proposes to add another resistor in parallel with it.


Homework Equations



a) What value should she use for the second resistor

b) Determine the effective resistance of the combination

The Attempt at a Solution



I have no idea how to work this out. The answers are

a) 6.7 kOhms

b) 2.5 kOhms

I just need to know how to get to that answer
 
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Voltage drop across the "equivalent" resistance, meaning the resistance shown by the 2 resistances in parallel, equals 5V.

V = I*R => R = V/I

R = 5V/2mA = 2,500 OhmsNow this R is the equivalent resistance R_eq, which can be found by:

1/R_eq = 1/R1 + 1/R2

or after rearranging: R_eq = R1*R2/(R1+R2) , where you know one of the resistors (R1 = 4 kOhm).
 

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