Electron accelerated through a potential difference of 26000

AI Thread Summary
An electron accelerated through a potential difference of 26,000 V experiences a loss of electric potential energy, which can be calculated using the equation U=qV. This loss translates into kinetic energy, allowing for the determination of the electron's velocity as it exits the plates. The discussion highlights the importance of recognizing the relationship between potential energy and kinetic energy in solving physics problems. Participants express gratitude for clarifying this concept, indicating its significance in understanding the motion of the electron in a magnetic field. Further assistance is offered for analyzing the electron's motion upon entering the magnetic field.
iancurtis
Messages
6
Reaction score
0

Homework Statement


An electron is accelerated from rest through a potential difference of 26000 V, which exists between plates P1 and P2, shown below. The electron then passes through a small opening into a magnetic field of uniform field strength, B. As indicated, the magnetic field is directed into the page.

Homework Equations





The Attempt at a Solution


I've tried various ways of solving for velocity, but i always come to an equation where i am missing a variable. i tried finding the work so i could divide by the distance to get the force , but i was not given distance.
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    27.4 KB · Views: 1,186
Physics news on Phys.org
I had a very similar problem in my physics class, but it turns out there was just an equation that I was unaware of, namely U=qV where U is potential energy, q is a point charge, and V is the potential difference.
 
Well, when the electron is accelerated through two plates with a potential difference of 26000V, the electron has lost 26000V of electric potential. What does this tell you about the electric potential energy of the electron at the moment it exits the plates? In turn, what does that tell you about the kinetic energy of the electron at that point? That should get you on the right rack for finding the velocity.
 
Millacol88 said:
Well, when the electron is accelerated through two plates with a potential difference of 26000V, the electron has lost 26000V of electric potential. What does this tell you about the electric potential energy of the electron at the moment it exits the plates? In turn, what does that tell you about the kinetic energy of the electron at that point? That should get you on the right rack for finding the velocity.

thank you so much man, can't believe i didn't think of that. its so obvious now.
 
iancurtis said:
thank you so much man, can't believe i didn't think of that. its so obvious now.

No problem. :smile: If you need some help analyzing its motion, when it enters the magnetic field, just post again. :wink:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top