Electron Motion Near Nucleus: Calculating Period and Velocity

  • Thread starter Thread starter blueskadoo42
  • Start date Start date
  • Tags Tags
    Electron Nucleus
AI Thread Summary
The discussion revolves around calculating the period and velocity of an electron moving near a radon nucleus, given the electric field and force acting on it. The user has correctly calculated the electric field and force but struggles with determining the angular frequency (omega) and subsequently the period and velocity of the electron's motion. They attempted to use the formulas for angular frequency and centripetal acceleration but are unsure where their calculations are failing. Clarification on the application of these equations and the correct values for mass and radius is needed. The user seeks assistance to resolve their confusion and complete the calculations accurately.
blueskadoo42
Messages
26
Reaction score
0

Homework Statement


What is the magnitude of the electric field at a distance of 5.00 ×10−10 m from a radon nucleus?
=4.95×1011 N/C
What is the magnitude of the force on an electron at that distance?
=7.94×10-8 N
Now here is where I am getting stuck..
Treating the electron classically, that is, as a point object that can move around the nucleus at reasonably slow speeds, what is the period of the electron's motion? &
Again treating the electron classically, how fast it it moving?


Homework Equations


T=2Pi/omega
a=v^2/r
f=mr omega^2


The Attempt at a Solution



i tried solving for omega by plugging in the force, radius and mass of radon. then square rooting the answer. so ill have omega and then i take 2 pi over it right? for the period.. that's not working.
then i tried solving for the velocity by taking the force * radius / mass then square rooting that as well to find the velocity and that is wrong...

i don't know where i am going wrong.. any help would be great.

thanks!
 
Physics news on Phys.org
bump!
 
bump!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top