Energy of an ideal gas given its multiplicity

felipedc
Question:
The multiplicity of an ideal gas is given by g(U) = A.U3N/2, where U is the energy of the gas, A is a constant and N is the number of particles in the gas.
Prove that the energy of the gas given a temperature T is U = (3/2).N.kb.T

Attempts:
My first thought was to work with the entropy equation (S = kb * ln(g(U))) , but after isolating the variable U from the equation, I see no other way out.
Then I thought I should start by finding the probability of a system having energy U, and find the mean of all possibles energies. But that does not depend on variable g(U).

How should i proceed?
 
Physics news on Phys.org
felipedc said:
My first thought was to work with the entropy equation (S = kb * ln(g(U))) , but after isolating the variable U from the equation, I see no other way out.

This is the correct first step.

Do you know how the temperature is related to the entropy?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top