Calculating Average Force on Proton in Metal Film

AI Thread Summary
To calculate the average force opposing the proton's motion through the metal film, first determine the change in velocity, which is from 5.0x10^6 m/s to 2.0x10^6 m/s. Using the equation for force, F = mass * acceleration, the acceleration can be found using the kinematic equation that relates initial velocity, final velocity, acceleration, and distance. The thickness of the film (0.010 mm) serves as the distance over which the force acts. By applying these principles, the average force can be calculated accurately.
dcangulo
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A proton (m=1.67x10^-27 kg) that has a speed of 5.0x10^6 m/s passes through a metal film of thickness 0.010mm and emerges with a speed of 2.0x10^6 m/s. How large an average force opposed its motion through the film??

can anybody give me a clue on where i can start?
 
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Force, F = mass * acceleration.

There is an equivalence between energy and force applied over distance.

If a mass is accelerated uniformly (at an acceleration a) from velocity v1 to velocity v2 over a distance x, what is the relationship between v1, v2, a and x?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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