Equivalent Resistance of an RLC circuit

AI Thread Summary
The discussion revolves around calculating the equivalent resistance of an RLC circuit for a homework problem. Initially, the user attempted to find the equivalent resistance but arrived at a value of 7.5 ohms, which contradicts the book's answer of 2 ohms. After reevaluating the circuit by opening the switch and removing the sources, the user identified that only the rightmost loop remains, consisting of a 2-ohm resistor, a 2H inductor, and a 1F capacitor. The user seeks confirmation on whether this revised approach is correct. The discussion highlights the importance of accurately interpreting circuit configurations in RLC analysis.
wiz0r
Messages
56
Reaction score
0

Homework Statement


It is in the attachment.

NOTE: I supposed I did a little mistake when I drew the circuit with PSpice. The closed switch should look like .---->. instead of having that 45 angle. I don't know if it matters or not, so yea..


Homework Equations



Rp = (R1 * R2)/ (R1 + R2)
Rs = R1 + R2 + R3 + ... + Rn
α(series) = Req / (2*L)
Wo = 1/sqrt(LC)

The Attempt at a Solution



Okay, well, I'm trying to solve this second order transient circuit, but I have a problem! I can't find the correct equivalent resistance. What I do first is to remove the voltage source by a short and the current source by an open circuit. Now, I got to find the equivalent resistance to calculate α. What I do is;

R12 = (2 * 6) / (2 + 6) = 1.5 ohms

then;

Req = R12 + R3 + R4 = 1.5 + 4 + 2 = 7.5 ohms

According to the book, the Req should be 2 ohms! So either, I'm doing something really wrong, or there's a mistake with the book. Can someone please help me?

Any help would be greatly appreciated.
 

Attachments

  • circ.JPG
    circ.JPG
    22 KB · Views: 754
Physics news on Phys.org
mm, well, i figured out what was wrong.

since the switch is closed, i need it to open it to find the equivalents R, L, and C to check if its an series RLC or parallel RLC.

i opened the switch, and took out the sources, everything cancels out, and i'll have only the rightmost loop with the 2 ohm resistance, 2H inductance, and 1F capacitance.

anyway, could somone tell me if I am right or not?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...

Similar threads

Back
Top