Evaluate the double integral by converting to polar coordinates

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alanthreonus
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Homework Statement


Convert to polar coordinates to evaluate

[tex]\int^{2}_{0}\int^{\sqrt(2x-x^2)}_{0}{\sqrt(x^2+y^2)}dydx[/tex]

The Attempt at a Solution



Really I'm just not sure how to convert the limits of integration. I know [tex]\sqrt(2x-x^2)[/tex] is a half-circle with radius 1, but I'm not really sure where to go from there.
 
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A half-circle with radius 1 would be y=sqrt(1-x^2), not what you wrote.
 
Woops, I meant sqrt(2x-x^2)