Evaluate the double integral by converting to polar coordinates

  • #1

Homework Statement


Convert to polar coordinates to evaluate

[tex]\int^{2}_{0}\int^{\sqrt(2x-x^2)}_{0}{\sqrt(x^2+y^2)}dydx[/tex]


The Attempt at a Solution



Really I'm just not sure how to convert the limits of integration. I know [tex]\sqrt(2x-x^2)[/tex] is a half-circle with radius 1, but I'm not really sure where to go from there.
 
Last edited:

Answers and Replies

  • #2
rock.freak667
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By √(2x-x) do you mean just √x ?
 
  • #3
ideasrule
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A half-circle with radius 1 would be y=sqrt(1-x^2), not what you wrote.
 
  • #4
Woops, I meant sqrt(2x-x^2)
 

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