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Evaluate the double integral by converting to polar coordinates

  1. Mar 15, 2010 #1
    1. The problem statement, all variables and given/known data
    Convert to polar coordinates to evaluate


    3. The attempt at a solution

    Really I'm just not sure how to convert the limits of integration. I know [tex]\sqrt(2x-x^2)[/tex] is a half-circle with radius 1, but I'm not really sure where to go from there.
    Last edited: Mar 15, 2010
  2. jcsd
  3. Mar 15, 2010 #2


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    By √(2x-x) do you mean just √x ?
  4. Mar 15, 2010 #3


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    A half-circle with radius 1 would be y=sqrt(1-x^2), not what you wrote.
  5. Mar 15, 2010 #4
    Woops, I meant sqrt(2x-x^2)
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