Evaluating Integrals using the Residue THM

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Homework Help Overview

The discussion revolves around evaluating the integral of the function sin(z)/z² over the contour where |z|=1, utilizing the Residue Theorem. Participants are exploring the nature of the poles of the function involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning which residue rule to apply based on the type of pole present in the function sin(z)/z². There is uncertainty about whether to integrate first or determine the residue directly.

Discussion Status

Some participants have identified potential poles of the function and are discussing their nature. There is a mix of opinions regarding the classification of the pole at z=0, with some suggesting it may be a simple pole while others consider it a double pole. The conversation is ongoing with no clear consensus reached.

Contextual Notes

Participants are navigating the definitions and implications of different types of poles as they relate to the application of the Residue Theorem. There is a noted confusion regarding the correct approach to take in the evaluation process.

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Homework Statement



integral |z|=1 of sinz/z2dz


Homework Equations


Rule #1 if f(z) has a simple pole at z0, then
Res[f(z),z0] = lim(as z goes to z0) (z - z0)*f(z)

Rule #2 if f(z) has a double pole at z0, then
Res[f(z),z0] = lim(as z goes to z0)d/dz (z - z0)2*f(z)

Rule #3 If f(z) and g(z) are analytic at z0, and if g(z) has a simple zero at z0 then,
Res[f(z)/g(z), z0] = f(z0)/g'(z0)

Rule #4 If g(z) is analytic and has a simple zero at z0 then,
Res[1/g(z), z0] = 1/g'(z0)





The Attempt at a Solution



Just confused on which one to use? Would I integrate first? And if so what would my z0 be in Rest[..., z0]

Thanks
 
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What kind of of pole does the function sinz/z2 have and where is it? Although I think 1 and 2 will give the same result.
 
phsopher said:
What kind of of pole does the function sinz/z2 have and where is it? Although I think 1 and 2 will give the same result.

double pole at i/2 and -i/2?

Edit: Actually simple pole at z = 0?
 
Last edited:
Yep.
 

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