Find Center of Mass of Homogeneous Semicircular Plate

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To find the center of mass of a homogeneous semicircular plate, integration is necessary, particularly considering the variable radius as slices are taken. The user is exploring the setup of two integrals: one for the radius and another for the y-coordinate of the center of mass (Ycm). In a separate question regarding a cube box, the user struggles to calculate the z-coordinate of the center of mass (Zcm) and attempts a complex method that yields an incorrect result. A simpler approach is requested for determining Zcm, while the user also confirms their earlier calculation for the semicircular plate's center of mass as 4R/3π. The discussion emphasizes the challenges and methods involved in calculating centers of mass for different shapes.
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Find the center of mass of a homogeneous semicircular plate, let R be the radius of the circle.
I have think I need to use ingergration to slove this problem, I'm stuck with that R is also changing as if I'm cutting little slices, so does that mean i have to set up two intergra, one for R solve that, and put it into another intergra which is for Ycm?

another question is there is a cube box with no top lays on a coordinate system x,y,z, z is vertical. and the side is 40 cm, I can find xcm=20 and ycm=20 very easily, but i had a hard time to find z, and i used harder way to find z, which is tp set zcm=x, and calculate the weight between the top half of the box and bottom half of the box,
40(40-x)+2(40-x)2=20*20+40x+40x.
from there I got Zcm=17.5, and that is not even the right answer, can u guys suggest a better and easier way for me to slove it?
 
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X=\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\frac{xdm}{M}
 
huh, i got it, 4r/3pi is my answer, is that right?
 
could anybody give me a hint on my question #2, please
 
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