Find Electric Flux Through Surface 2

AI Thread Summary
To find the electric flux through surface 2, the correct formula is EAcosθ, where E is the electric field strength and θ is the angle between the electric field and the normal to the surface. Given the uniform electric field of 200 N/C and an area of 3.90 m², the angle used should be 55° (90° - 35°) instead of 35°. The calculation for the flux through surface 2 should therefore be (200)(3.90)cos(55), leading to the correct answer. Misapplying the angle resulted in an incorrect initial calculation. Understanding the correct angle is crucial for accurate flux determination.
cass
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Homework Statement



The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 2.20 m², while surface (2) has an area of 3.90 m². The electric field in the drawing is uniform and has a magnitude of 200 N/C. Find the magnitude of the electric flux through surface (2) if the angle θ made between the electric field with surface (2) is 35.0°.
18-81.jpg

Homework Equations



I used gausse law

The Attempt at a Solution



(200)(2.20)cos(35)=360.4
(200)(3.90)cos(35)=638.9
Sinnce they are looking for magnitude of surface 2 I thought the answer was 638.9 but I got it wrong.[/B]
 
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You used cos(35) when calculating the flux through surface 2. Think about whether or not you used the correct angle here.
 
what do u mean?
 
ok since it is a 90 degree angle then subtracting 35 should give me 55 right?
 
cass said:
ok since it is a 90 degree angle then subtracting 35 should give me 55 right?
Yes, using Gauss' Law, EAcosθ, where θ refers to the angle between the electric field's direction and the line perpendicular to the area of application (which is the dot product of E and A, E⋅A)
 
thank u!
 
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