Find emf and the inner resistor of the battery

AI Thread Summary
The discussion focuses on calculating the electromotive force (emf) and internal resistance of a battery using two different resistors, R1 and R2, with corresponding currents I1 and I2. The key equations derived include I1 = emf / (R1 + r) and I2 = emf / (R2 + r), leading to the relationship I1(R1 + r) = I2(R2 + r). The internal resistance is expressed as r = (R2I2 - I1R1) / (I1 - I2), and emf can be found using the formula emf = I1I2(R2 - R1) / (I1 - I2). The calculations presented appear to be correct, confirming the approach taken to solve the problem.
prishila
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Homework Statement


When the resistor is R1, in the circle there is the intensity I1 and when the resistor is R2, the intensity becomes I2.Find emf and the inner resistance.[/B]

Homework Equations


I=emf/R+r

The Attempt at a Solution


I1=efm/R1+r
I2=efm/R2+r
efm is equal
I1*(R1+r)=I2(R2+r)
r=(I2R2-I1R1)/(I1-I2)
And how can I find emf?
 
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Can I rephrase the problem statement as :
With a resistor R1 connected to a battery, the current is I1.
With a resistor R2 connected to a battery, the current is I2.
Find emf and the internal resistance.
Your equation requires brackets: ## I_i = emf / (R_i + r_{internal})##

So you have two equations with two unknowns: ## emf## and ##r_{internal}##. Can you write them down and post ?

And: the mentor will move this thread to introductory physics homework.

--
 
BvU said:
Can I rephrase the problem statement as :
With a resistor R1 connected to a battery, the current is I1.
With a resistor R2 connected to a battery, the current is I2.
Find emf and the internal resistance.
Your equation requires brackets: ## I_i = emf / (R_i + r_{internal})##

So you have two equations with two unknowns: ## emf## and ##r_{internal}##. Can you write them down and post ?

And: the mentor will move this thread to introductory physics homework.

--
Here's what I did
efm=I1*(R1+r)=I2*(R2+r)
I1*(R1+r)=I2*(R2+r)
I1/I2=(R2+r)/(R1+r)
I1R1+I1r=R2I2+I2r
r(I1-I2)=R2I2-I1R1
r=(R2I2-I1R1)/(I1-I2)
I replaced R with what I found and it results
efm=I1I2(R2-R1)/(I1-I2)
Did I find efm and r correctly?
 
Last edited:
prishila said:
efm=I1/(R1+r)=I2/(R2+r)
V=IR and not I/R.
 
cnh1995 said:
V=IR and not I/R.
You're right. i corrected it
 
prishila said:
I1/I2=(R2+r)/(R1+r)
I1R1+I1r=R2I2+I2r
r(I1-I2)=R2I2+I1R1
Check the 3rd equation.
 
cnh1995 said:
Check the 3rd equation.
Corrected
 
prishila said:
Here's what I did
efm=I1*(R1+r)=I2*(R2+r)
I1*(R1+r)=I2*(R2+r)
I1/I2=(R2+r)/(R1+r)
I1R1+I1r=R2I2+I2r
r(I1-I2)=R2I2-I1R1
r=(R2I2-I1R1)/(I1-I2)
I replaced R with what I found and it results
efm=I1I2(R2-R1)/(I1-I2)
Did I find efm and r correctly?
Looks correct!
 
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