Find Fmax for a 450g Particle Moving Along the x-Axis | Ex11.15

  • Thread starter Thread starter ChrisMC
  • Start date Start date
AI Thread Summary
To find Fmax for a 450 g particle moving along the x-axis, the maximum force occurs at 1 meter on the force versus distance graph. The particle's velocity increases from 4.0 m/s to 7.5 m/s between 0 m and 2 m. The work-energy theorem is applicable, where the change in kinetic energy (ΔKE) equals the net work done (WNet). By calculating ΔKE using the initial and final velocities, and considering the area under the force curve, the correct maximum force is determined to be approximately 9.05625 N. This approach effectively utilizes the relationship between force, mass, and acceleration to solve the problem.
ChrisMC
Messages
17
Reaction score
0
A 450 g particle moving along the x-axis experiences the force shown in Figure Ex11.15. The particle goes from vx = 4.0 m/s at x = 0 m to vx = 7.5 m/s at x = 2 m. What is Fmax?

Where the maximum peak on the force by distance graph is at 1m

F=ma
v=d/t
a=v/t


I have no idea how to answer this. I tried to find the acceleration then multiply it by the mass

i got 7.2 n which was wrong
 
Physics news on Phys.org
Use the work energy theorem
ΔKE = WNet
You can calculate the change in kinetic energy using the given numbers. Since only F is acting on the particle, F is the net force. The work done by F is the area under the curve, so ...
 
.5mv^2-.5mv^2 using 7.5 and 4 as the velocities. thank you very much

9.05625 btw
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top