If you think that the book's answer ##\pi (15+8 \ln(4))## is close to the correct answer you are very much mistaken. The correct answer is yours, except that the approximation ##\pi = 3.14## is way too crude---just leave it as symbolic ##\pi## until it comes time to evaluate the final answer numerically. Look at the following:
\begin{array}{rccc}<br />
\pi (15 - 8 \ln\,4 )& \doteq & 12.28251236 & \doteq & 12.3 \\<br />
\pi (15 + 8 \ln\,4 ) & \doteq & 81.96526726 & \doteq & 82.0 \\<br />
\pi 15 & \doteq & 47.12388981 & \doteq & 47.1<br />
\end{array}<br />
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