Finding Acceleration in a Frictionless System with Multiple Masses

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Homework Help Overview

The discussion revolves around determining the acceleration of a system of three masses on a frictionless table, with specific masses provided. The original poster seeks to find the acceleration but notes the absence of a given force complicates the solution process.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants suggest drawing free body diagrams and isolating the forces acting on the blocks. There is mention of using Newton's second law to create equations based on these diagrams. Some express confusion about how to resolve the two unknowns involved in the problem, specifically the tension in the cable and the acceleration.

Discussion Status

The discussion is active, with participants providing guidance on isolating systems and applying Newton's laws. There is recognition of the uniform tension throughout the system, and multiple equations are suggested to address the unknowns. However, no consensus on a final approach or solution has been reached.

Contextual Notes

Participants are working under the assumption that the table is frictionless and are considering the implications of this on the forces acting on the masses. The lack of a specified force is noted as a constraint in finding the acceleration.

jessicax07
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Homework Statement



What is the acceleration of the masses as shown in the second attached image. m1 = 0.9kg, m2 = 1.6kg, and m3 = 2.4kg. (Assume the table is frictionless)

Homework Equations



[tex]\sum[/tex]F=ma
F_mg+FN = ma

The Attempt at a Solution



I figured everything up to the point a=F/(m1+m2+m3) but without the force given, how do you figure it out?
 

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Draw free body diagrams. Isolate the hanging block...what are the forces acting on it? Then use Newton 2 on that blck to arrive at an equation. Then isolate the 2 blocks together on the table, determine the forces acting on that free body diagram of those 2 blocks, and apply Newton 2 to that system to get another equation. Now you solve 2 equations with 2 unknowns to find he aceleration. Note that the magnitude of the acceleration of each block must be the same.. Note also that the magnitude of the tension in a cord wrapped around an ideal pulley is the same on both sides of the pulley.
 
Even by doing that though, I don't see how I'd find a because like you said there would be 2 unknowns...
 
jessicax07 said:
Even by doing that though, I don't see how I'd find a because like you said there would be 2 unknowns...
Yes, the 2 unknowns are the cable tension, T, and the acceleration, a. Solve the 2 simultaneous equations by the method of your choice.
 
Tension is uniform through out the entire net system. Knowing that, isolate each system (isolate each block), sum the forces in each system and then use substitution to find a. Obviously the forces in the y direction cancel the first two block is zero so you only need to work about Fx. The forces in the x direction for the third block are zero, so you only need to worry about the y direction
 

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