Finding an electric field on a disk using surface charge density

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SUMMARY

The discussion focuses on calculating the electric field produced by a disk with a radius of 2.30 cm and a surface charge density of 5.22 μC/m² at a point on its central axis, located 11.2 cm away from the disk. The relevant formula for the electric field is derived from integrating the contributions of elementary rings of charge on the disk, expressed as (int)dEz = σ/2ε₀ (1 - z/√(z² + r²)). This approach effectively utilizes calculus to determine the resultant electric field at the specified distance.

PREREQUISITES
  • Understanding of electric fields and surface charge density
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of the constants ε₀ (permittivity of free space)
  • Basic principles of electrostatics and charge distribution
NEXT STEPS
  • Study the derivation of the electric field from continuous charge distributions
  • Learn about the application of Gauss's Law in electrostatics
  • Explore the concept of electric field lines and their significance
  • Investigate the effects of varying surface charge densities on electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by charged objects.

gretchin
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Homework Statement



A disk of radius 2.30 cm has a surface charge density of 5.22 μC/m2 on its upper face. What is the magnitude of the electric field produced by the disk at a point on its central axis at distance z = 11.2 cm from the disk?


Homework Equations



Formula for an electric field

The Attempt at a Solution



(int)dEz= sigma/2ep0 (1-z/sqrt(z^2+r^2)
 
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Break up the disk into elementary rings and integrate.
 

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