Finding Initial Temperature Entropy and Heat Exchange

AI Thread Summary
The discussion revolves around calculating the initial temperature of water when a hot aluminum pan is submerged in it, given the system's entropy change. The equations used include heat transfer formulas and entropy calculations, with specific heat capacities for water and aluminum provided. Despite multiple attempts to solve the equations, the correct initial temperature of 16 degrees Celsius remains elusive for the poster. Participants suggest verifying the calculations and substituting the known answer back into the equations to check for consistency. The conversation emphasizes the importance of careful equation manipulation and substitution in thermodynamic problems.
Luke Strand
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Homework Statement


A 2.45 kg aluminium pan at 155 C is plunged into 3.58 kg of water. If the entropy change of the system is 162 J/k, what is the initial temperature of the water?

Homework Equations


Q = mcΔT ΔS=mcln(T_2/T_1) Q_water + Q_Aluminium = 0
c water = 4184 J/kg*K c aluminium = 900 J/kgK
3. Attempted Solutions
T_i Aluminum = 155
T_f is the same for the water and aluminium
T_i where T_i is the initial temperature of the water.
162 = (3.58)(4184)(ln(T_f/T_i) + (2.45)(900)ln((T-f)/(428))
(3.54)(4814)(T_f-T_i) + (2.45)(900)(T_f - 428)= 0

After solving this system of equations multiple times I can't seem to get the correct answer. The answer is 16 degrees C but I am not sure how to get there.
 
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Luke Strand said:

Homework Statement


A 2.45 kg aluminium pan at 155 C is plunged into 3.58 kg of water. If the entropy change of the system is 162 J/k, what is the initial temperature of the water?

Homework Equations


Q = mcΔT ΔS=mcln(T_2/T_1) Q_water + Q_Aluminium = 0
c water = 4184 J/kg*K c aluminium = 900 J/kgK
3. Attempted Solutions
T_i Aluminum = 155
T_f is the same for the water and aluminium
T_i where T_i is the initial temperature of the water.
162 = (3.58)(4184)(ln(T_f/T_i) + (2.45)(900)ln((T-f)/(428))
(3.54)(4814)(T_f-T_i) + (2.45)(900)(T_f - 428)= 0

After solving this system of equations multiple times I can't seem to get the correct answer. The answer is 16 degrees C but I am not sure how to get there.
Your setup is correct. Please show us what you did in attempting to solve the equations. Did you try substituting 16 C into the equations?
 
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