Finding length and diameter of copper wire

AI Thread Summary
To find the length and diameter of a copper wire made from 1.0 g of copper with a resistance of 0.5 ohms, first calculate the volume using the mass and density of copper, which results in a volume of 1.12 x 10^-4 m^3. The volume of a cylinder is given by the formula V = πr²h, where r is the radius and h is the length. By expressing the diameter in terms of the length and substituting it into the resistance formula, the diameter can be determined by solving the equation for resistance, given the resistivity of copper. The process involves setting the resistance equation equal to 0.5 ohms and solving for the diameter, which then allows for the calculation of the wire's length. Understanding these relationships is key to solving the problem effectively.
dev-hud
Messages
15
Reaction score
0
Suppose you wish to fabricate a uniform wire out of 1.0 g of copper (Density of copper is 8.93 x 10^3 kg/m^3). If the wire is to have a resistance of R = .5 ohms, and all the copper is to be used, what will

a) the length and
b) the diameter of this wire?



this has me tottally confuzed because i can not put together a formula to find length or the diameter of the wire. Help?
 
Physics news on Phys.org
You can compute the volume of the wire from the mass and the density.

If you know the diameter is equal to d, you can compute the length of the wire (from the equation for the volume of a cylinder)

If you know the length and the diameter, you can compute the resistance (resistivity of copper is 1.72 \cdot 10^{-8} \Omega m )

The resistance will be a function of the chosen diameter d. Set this equal to 0.5 and you can find d
 
ok thank you.

so if i have a volume of 1.12 x 10^-4, and the equation for volume of a cylinder is (pi)(h)(r^2), i don't get how to computer the length if i do not have a height or a radius? and then i need the length and diameter to get resistance (given at 0.5), how do i get this into finding the diameter?

i am confuzed on what formula to use or how do use volume of a cylinder to get d??
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top