- #1

Sean1218

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**Finding period of revolution of an electron (fairly urgent)?**

## Homework Statement

A doubly ionized atom (charge = +2e) whose mass is 3.65E-26 kg is accelerated by a voltage of 3950.0 V and enters a region where a uniform magnetic field B = 0.0500 T acts perpendicular to its motion.

a) What is the radius of curvature of the path of the ion in the B-field?

b) What is its period of revolution?

## Homework Equations

F=QvB

F=m4pi

^{2}r/T

^{2}

F=mv

^{2}/r

## The Attempt at a Solution

I did the first part, the correct answer is 0.601 m.

I've tried a few different methods for b), I won't list them all.

I rearranged the third equation for v, plugged it into the first equation, plugged that into the second equation and rearranged for T.

T=√(4π

^{2}m

^{2}/(Q

^{2}B

^{2}))

Solved that for 0.0000143156 s

No idea if this is right or not, but I doubt it because I think I need to use voltages and energies, but that didn't work when I tried it.