Finding time of a proton travelling in an electric field?

AI Thread Summary
To determine the time it takes for a proton to travel between two plates in an electric field of 200 N/C, the force on the proton is calculated using F = qE. This force leads to the proton's acceleration, which can be found using Newton's second law (F = ma). By applying kinematic equations and assuming the proton starts from rest, the time of travel can be computed. The final result for the time taken is approximately 5.775 x 10^-10 seconds. This calculation confirms the importance of considering the proton's mass in the analysis.
newtonsapple
Messages
2
Reaction score
0
1. There is an electric field with two plates, one positive one negative, having a distance of 4.5x10-3 metres apart producing a charge of 200N/C. How long would it take a free moving proton to travel from the positive plate to the negatively charged plate?

2. ?

3. I solved for voltage, coulombs, Newtons, joules.. I just can't think of an equation for getting time. There are several for power, I just need either amperes, or ohms. thanks!
 
Physics news on Phys.org
Force on a proton in an electric field is F = qE = ma.
Find acceleration of the proton.
Using kinematic equation find the time it takes to travel a certain distance assuming that proton starts from rest.
 
sweet dude, thanks a lot for your help! I solved the bad boy right away. :approve: I forgot that a proton has a constant mass too. duh. :redface: I got aprox. 5.775x10-10s. :rolleyes: I think that sounds about right...
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top