- #1

jitto92

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## Homework Statement

A firefighter, 44.0 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 31.2° above the horizontal. If the speed of the stream as it leaves the hose is 40.0 m/s, at what height will the stream of water strike the building?

v=40.0m/s

v(x)=vcos31.2

v(y)=vsin31.2

g=9.81

## Homework Equations

R=(vsin^2(31.2))/g

x(t)=vcos(31.2)

## The Attempt at a Solution

I have tried breaking it down to x and y components but it doesn't make sense if the height of the building and its distance from the firefighter is not given !