Flux Integral for a Surface Above a Disc with Downward Orientation

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QUESTION: Compute the flux of the vector field, F , through the surface, S.

F = xi+yj+zk

S is the part of the surface z = x^2 + y^2 above the disc x^2 + y^2 ≤ 4 , oriented downward.

I am just wondering why the integrand is from o to 4 while the radius is only 2.

bewjcz.jpg
 
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It isn't. That's incorrect. It should be 2.
 
My solution guide says otherwise, along with my online homework
 
HallsofIvy said:
It isn't. That's incorrect. It should be 2.

I just emailed my teacher and he said there was an error in the online homework. The correct answer is indeed used with radius 2. Sorry about that.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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