Force on projected object at its highest point. What is the net force?

AI Thread Summary
At the highest point of its trajectory, the net force on a ball thrown at an angle with no air resistance is solely due to gravity. The weight of the ball is 1.0 N, which means the gravitational force acting on it is 1 N downward. Since there are no other forces acting on the ball, the net force is 1 N down. The initial assumption that the net force could be zero or 4.9 N is incorrect. Therefore, the conclusion is that the net force at the highest point is 1 N downward.
peterpam89
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Homework Statement


A ball with a weight of 1.0 N is thrown at an angle of 30 degrees above the horizontal with an initial speed of 12 m/s. There is no air resistance acting on the ball. At its highest point, the net force on the ball is:
A. 4.9 N, 30 degrees below horizontal
B. zero
C. 4.9 N up
D. 4.9 N down
E. None of the above

Homework Equations


Fnet= ma

The Attempt at a Solution



I am guessing that since there is no wind resistance, there is no acceleration in the X direction. Thus, the horizontal force is zero.

The force in the y direction should remain constant because gravity is a constant (9.8 m/s^2) and the mass is a constant. Thus, I am thinking that the net force should equal 1N.
My answer would be E. None of the above. I always get paranoid about choosing none of the above as my answer. Could someone please confirm that this is the proper way of going about this question?

Thank you so much!
-peterpam89
 
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peterpam89 said:

Homework Statement


A ball with a weight of 1.0 N is thrown at an angle of 30 degrees above the horizontal with an initial speed of 12 m/s. There is no air resistance acting on the ball. At its highest point, the net force on the ball is:
A. 4.9 N, 30 degrees below horizontal
B. zero
C. 4.9 N up
D. 4.9 N down
E. None of the above


Homework Equations


Fnet= ma


The Attempt at a Solution



I am guessing that since there is no wind resistance, there is no acceleration in the X direction. Thus, the horizontal force is zero.

The force in the y direction should remain constant because gravity is a constant (9.8 m/s^2) and the mass is a constant. Thus, I am thinking that the net force should equal 1N.
My answer would be E. None of the above. I always get paranoid about choosing none of the above as my answer. Could someone please confirm that this is the proper way of going about this question?

Thank you so much!
-peterpam89

I would say your reasoning is spot on.

I hope I did not break any forum rules,
if so, I apologize.
 
Yup, it's 1 N. Gravity is the only force that can possibly act on the mass: there's no air resistance, friction, electromagnetism, nuclear forces, or divine intervention to consider, so the net force is due only to gravity and gravity exerts 1 N.
 
Great- thanks! :smile:
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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