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Gas chamber problem

  1. Dec 23, 2015 #1
    1. The problem statement, all variables and given/known data
    Consider a rectangular isolated(non-conducting) chamber as shown below. The chamber is divided into three compartments. The wall separating A and B has negligible mass, no friction and is conducting, while the wall separating B and C has negligible mass and friction and is non-conducting.

    Initially each compartment has the same amount of air at temperature T, volume V and pressure P. Now compartment A is slowly heated through a heater such that the final volume of C becomes 49V. Now my question is that once equilibrium is attained can I assume that each compartment would have the same pressure? According to the answer given in my book the final pressure in A and C are the same however in B has different pressure. Is this possible?

    2. Relevant equations
    PV=nRT

    3. The attempt at a solution
    since at equilibrium there is to be no movement of walls hence pressure should be the same in all the three chambers
     
  2. jcsd
  3. Dec 23, 2015 #2
    I don't see any figure. Did you forget to include it?
     
  4. Dec 23, 2015 #3
    thermodynamics.png
     
  5. Dec 23, 2015 #4
    There is a lot about this problem statement that doesn't make sense. If the total volume of the 3 chambers is 3V, how can the final volume of chamber C be 49V? Maybe the final volume of chamber C is supposed to be 0.49V? The final pressure in all 3 chambers has to be the same in order for mechanical equilibrium to prevail. If the wall separating A and B is frictionless, massless, and conducting, then, at final equilibrium, chambers A and B will be in exactly the same state of T, P, and V.

    Chet
     
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