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Gauss Law

  1. Apr 10, 2005 #1
    I used the formula (E * Area * cos(theta)) and got the wrong answer (.02529) and I really don't understand why. I need help

    The square surface shown measures 4.0 mm on each side. It is immersed in a uniform electric field with magnitude E = 1930 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take the normal to be "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.
     
  2. jcsd
  3. Apr 10, 2005 #2

    dextercioby

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    It looks correct (probably not the final #).U may have to check the units ([itex] \left(1\mbox{mm})\right)^{2}=10^{-6} \mbox{m}^{2} [/itex]...

    Daniel.
     
  4. Apr 10, 2005 #3

    HallsofIvy

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    35 degrees to the normal is 55 degrees to the surface. Did you try that?
     
  5. Apr 10, 2005 #4

    dextercioby

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    Halls,she needs the scalar product between the electric field vector and the normal to the surface,which make an angle of 35° between them...

    Daniel.
     
  6. Apr 10, 2005 #5
    I tried 55, and it didn't work.

    Is electrical flux supposed to be negative? Thats all I can think of. I don't know if that's right.
     
  7. Apr 10, 2005 #6

    dextercioby

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    Depends on the sense of the electric field.If it enters the page or not.Your problem is pretty vague in this issue,because you haven't provided the drawing/picture.

    Daniel.
     
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