The problem statement, all variables and given/known data How does the slope and y-intercept change if you reverse the x and y axis of a linear graph. Will the graph still be linear? The original y=mx+b format followed the physics equation: V^2 = 2a(d) + Vi^2 Therefore, when y was "V^2" while x was "d", the y-intercept was Vi^2 and the slope was equal to "2a". What are the y-int and slope once the axis are reversed, and x is "V^2" and y is "d"? The attempt at a solution I'm sure this is quite simple, but for some reason I am stumped. I realize the new graph would still be linear, reflected along y=x. I tried inserting the new x and y values into the equation, getting: x = my + b (x - b)/m = y (v^2 - vi^2)/2a = d so (v^2)(1/2a) - (vi^2)/2a = d leaves the new equation in the form of mx + b = y with m = 1/2a and b = (-vi^2)/2a Have I come to the correct solution? Thanks a lot!!