Help with Simple High School Physics

AI Thread Summary
To find momentum with only mass and height, consider the relationship between potential energy and kinetic energy. When an object is dropped, its potential energy converts to kinetic energy, allowing for the calculation of momentum at impact. The formula for momentum is p=mv, where m is mass and v is velocity, which can be derived from the height using energy conservation principles. If the object is initially at rest, its momentum is zero until it falls. Further clarification on the specific problem can enhance understanding and provide a more accurate solution.
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Help with "Simple" High School Physics

Hey, does anyone know how to find the momentum when you only have mass and height?
 
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How does potential energy relate to kinetic energy?
 
I think it's a trick. Is momentum proportional to energy?
 
I have a problem on a physics assignment to find momentum and all I'm given is the mass and a height. Once I come up with a formula for that I should be able to find the rest. Any ideas?
 
p=mv.. so if its not moving then momentum is zero. there has to be some context like maybe the final momentum when a mass is dropped from a height? or something...
 
ok this post wasnt really detailed but thx...ive put up a new one though..."Finding momentum with height and mass" that has the problem and all
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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