HOmework : Addition of Vectors by Means of Components

AI Thread Summary
The discussion revolves around calculating the resultant displacement of a grasshopper's four jumps, each defined by specific vectors. The user expresses confusion about the calculations but demonstrates an understanding of vector components. A suggestion is made to check the calculator settings, ensuring it is set to degrees rather than radians, which could affect the accuracy of the results. The calculations for the x and y components of each vector are presented, but the user is encouraged to verify their results for accuracy. Proper settings and careful calculations are essential for determining the correct magnitude and direction of the resultant displacement.
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1. A grasshopper makes four jumps. THe siplacement vectors are (1) 27 cm, due west; (2) 23 cm, 35 degrees south of west; (3) 28 cm, 55 degrees south of east; and (4) 35 cm, 63 degrees north of east. Find the magnitude and direction of the resultant displacement. Express the direction with respect to due west



Homework Equations


I'm a litle confused with almost everything. I know how to draw the picture though.


The Attempt at a Solution


A= 27 cm
Angle A=180
B=23 cm
Angle B= 35 degres
C= 28 cm
Angle C= 55 degrees
D= 35 cm
Angle D= 63

Ax=Acos0a
= -116.6 cm
Bx=Bcos0b
= -20.8
Cx= -.67 cm
Dx=Dcos0d
=34.5 cm

Ay=Asin0A
= -21.63
By= -9.8 cm
Cy= -27.9 cm
Dy= 5.9 cm

Rx= ax + bx + cx + dx
=Rx= -2.23

Ry= ay+ by + cy + dy
Ry= -53.43 cm

R^2= rx^2 + ry^2
= 53. 48 cm

Angle R= ry/rx
=181.53 degres.
 
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Hi oreocookie,

oreocookie said:
1. A grasshopper makes four jumps. THe siplacement vectors are (1) 27 cm, due west; (2) 23 cm, 35 degrees south of west; (3) 28 cm, 55 degrees south of east; and (4) 35 cm, 63 degrees north of east. Find the magnitude and direction of the resultant displacement. Express the direction with respect to due west



Homework Equations


I'm a litle confused with almost everything. I know how to draw the picture though.


The Attempt at a Solution


A= 27 cm
Angle A=180
B=23 cm
Angle B= 35 degres
C= 28 cm
Angle C= 55 degrees
D= 35 cm
Angle D= 63

Ax=Acos0a
= -116.6 cm
Bx=Bcos0b
= -20.8
Cx= -.67 cm
Dx=Dcos0d
=34.5 cm

Ay=Asin0A
= -21.63
By= -9.8 cm
Cy= -27.9 cm
Dy= 5.9 cm

I believe your calculator is set to radians instead of degrees. Try them again (being careful with the signs and the decimal points) and see what you get.
 
Your method is correct, but if the numbers are wrong, your calculator could indeed be set on the wrong setting. Make sure it is set to "Degrees" and NOT "Radians."

On a TI-83, this can be done by punching the "MODE" button and then selecting "Degrees."
 
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