How do I calculate internal forces in a beam bending problem?

In summary, the conversation discusses a problem with determining internal forces in a beam bending situation. The suggested approach is to use the equation M = EI*d2y/dx2 and the relationship between bending moment and internal force, F = dM/dx. By integrating the bending moment from x=0 to x=L, the total internal force at point C can be calculated. From there, the individual forces at points A and B can be determined by subtracting the force due to tension in the cable.
  • #1
egikm
3
0
Hello,
I am having difficulties trying to work out one problem. I've attached a picture explaining the situation - the task is to determine internal forces in C but the bending moment M(x) doesn't seem to get me the correct results (I used equivalance and went from LHS). I would greatly appreciate if somebody helped me construct a correct equation or find the mistake, thank you.
 

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  • #2
The problem you are trying to solve is a classic beam bending problem. The basic equation for a beam in bending is M = EI*d2y/dx2, where M is the bending moment, E is Young's modulus, I is the moment of inertia, and dy/dx is the slope of the beam at any point along its length.

In your case, you need to solve for the internal forces in C. To do this, you will need to use the relationship between the bending moment, M, and the internal force, F, which is given by the equation F = dM/dx.

Using this equation, you can calculate the internal forces in C by integrating the bending moment M(x) from x=0 to x=L:

F(C) = ∫M(x)dx from x=0 to x=L

This will give you the total internal force at point C due to the bending moment.

Once you have this value, you can then calculate the individual forces at points A and B by subtracting the force due to the tension in the cable.

Hope this helps!
 
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