How Do You Calculate Football's Velocity and Time to Reach Maximum Height?

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To find the football's velocity, calculate the magnitude using the Pythagorean theorem with the initial vertical and horizontal components, resulting in approximately 26.9 m/s at an angle determined by the inverse tangent of the vertical over horizontal components. For the time to reach maximum height, use the kinematic equations, specifically the formula t = v_y / g, where v_y is the initial vertical velocity and g is the acceleration due to gravity. The discussion emphasizes the importance of showing attempted work for better guidance. Engaging with the community can provide clarity on these physics concepts. Understanding these calculations is essential for solving projectile motion problems effectively.
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Question :
A boy kicked a football with an initial velocity component of 15.0m/s and a horizontal velocity component of 22.0m/s.
a)what is the velocity of the football(magnitude and direction)
b)how much time is needed to reach the maximum height?

(this is not my homework,it is a question which was not been discussed in class so I am not able to answer it.)
 
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Welcome to PF!

Hi mohammed1992! Welcome to PF! :smile:

(you mean "initial vertical component" :wink:)

I assume you can do (a).

For (b), you should have used the usual https://www.physicsforums.com/library.php?do=view_item&itemid=204" equations …

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(same for your other thread :wink:)
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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