Engineering How Do You Calculate Impedance in Filter Circuits?

AI Thread Summary
Calculating impedance in active filter circuits involves understanding both input and output impedances. For a simple low pass filter, the input impedance is R + Xc, while the output impedance is ZL || (RF + R1) when the input is shorted. In a second-order configuration, the output impedance from port A-B may need to account for the feedback capacitor and the input side with the source short-circuited. The approach to derive input impedance using KCL at the node is correct, involving the relationships between voltages and currents in the circuit. Seeking clarification on these calculations is essential for accurate impedance analysis in filter circuits.
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The Attempt at a Solution



Hi all, i have some doubts on how to find the impedances for active filter circuits.

Let's start with a simple low pass filter :

http://img85.imageshack.us/img85/6484/52244578oo4.th.jpg

The input impedance should be R + Xc; and the output impedance should be ZL || (RF+R1) once i short the input.

However, a same filter but at 2nd order configuration is confusing me. Assuming the circuit diagram is given as below :

http://img85.imageshack.us/img85/4529/lp2ia8.th.jpg

Will be output impedance be solely ZL || (RF+R1) if seen from port A-B ? Or will it have to include the feedback capacitor and the input side with the source short-circuited as well?

As for the input impedance, is this derivation method along the right line?

applying KCL at red node V1

Ii = I1 + I2
(Vi-V1)/R1 = (V1-Vo)/XC2 + (V1-0)/(R2+XC2)

where vo=KVx ; K is the DC voltage gain of the amplifier.

Vx = (V1*XC1)/(R2+XC1)

After that, from definition of Zi = Vi/Ii; try to arrange the equation to fit Vi/Ii?
 
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can someone please help answer this?
 
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