How Do You Calculate the Spring Constant for a Car's Shock Absorbers?

Click For Summary
SUMMARY

The calculation of the spring constant (k) for a car's shock absorbers involves understanding the relationship between the period of oscillation (T), mass (m), and the total spring constant when multiple springs are used. For a car with a mass of 1380 kg and a period of 1.81 seconds, the correct formula is k = (4π²m)/T², resulting in a spring constant of 101,806.60 N/m. It is crucial to account for the fact that the springs are in parallel, which means the effective spring constant is multiplied by the number of springs (4) in the system.

PREREQUISITES
  • Understanding of harmonic motion and oscillation principles
  • Familiarity with the formula for the period of a spring-mass system
  • Basic algebra for rearranging equations
  • Knowledge of parallel spring systems and their effective spring constants
NEXT STEPS
  • Study the derivation of the formula for the period of a spring-mass system
  • Learn about the dynamics of parallel spring systems
  • Explore the concept of natural frequency in mechanical systems
  • Practice solving problems involving multiple springs and oscillation
USEFUL FOR

Students studying physics, mechanical engineers, and anyone involved in automotive design or suspension systems will benefit from this discussion.

Bearbull24.5
Messages
50
Reaction score
0

Homework Statement


A car with bad shock absorbers bounces up and down with a period of 1.81 s after hitting a bump. The car has a mass of 1380 kg and is supported by four springs of equal force constant k. Determine a value for k.
Answer in units of N/m.


Homework Equations


T=2pi/w
T=1.81 s

w^2=k/m

The Attempt at a Solution


I solved for w in the above equation and got 11.372 as my answer. I then plugged it into the second equation and solved for k. I got an answer of 178,482.6366 which I immediately plugged in and got wrong. I then divided it by 4 thinking that would work. Nope got it wrong
 
Physics news on Phys.org
I did the same thing. I rearranged the equation and got k = (2pi/T)2 * m. And I got 101806.5992 for mine, and got it wrong. ?? Someone please help. Thanks. ;)
 
Bearbull24.5, I believe you solved for the frequency incorrectly (when you solved for w as a function of T, did you end up multiplying 2pi by T or dividing 2pi by T; which should you have done)?

And further, while you were supposed to divide by 4, you should have an understanding of why that is the case. The car is supported by 4 equal springs with spring constant k - these springs are in parallel, meaning that for a given force (the weight of the car), all 4 springs will move down the same amount. If you're looking at the natural frequency of this system, the total spring constant is 4*k. So w^2=4k/m. The rest of the problem is algebra and arithmetic.

MissPenguins, you've made an arithmetic error and forgotten about the factor of 4 described above.
 
jamesrc said:
Bearbull24.5, I believe you solved for the frequency incorrectly (when you solved for w as a function of T, did you end up multiplying 2pi by T or dividing 2pi by T; which should you have done)?

And further, while you were supposed to divide by 4, you should have an understanding of why that is the case. The car is supported by 4 equal springs with spring constant k - these springs are in parallel, meaning that for a given force (the weight of the car), all 4 springs will move down the same amount. If you're looking at the natural frequency of this system, the total spring constant is 4*k. So w^2=4k/m. The rest of the problem is algebra and arithmetic.

MissPenguins, you've made an arithmetic error and forgotten about the factor of 4 described above.

Alright, I figured it out and got the right answer. Thanks. ;)
 
I multiplied 2pi by T
 
Got it
 

Similar threads

Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K