How Do You Calculate the Velocity of a Rotating Vector?

AI Thread Summary
To calculate the velocity of a rotating vector, the angular velocity vector \(\vec{w}\) is determined using the cross product of vectors \(\vec{A}\) and \(\vec{C}\). The calculation shows that \(\vec{D} = \vec{A} \times \vec{C} = 7\hat{i} - 5\hat{j} + \hat{k}\), which is then used to express \(\vec{w}\) as a linear combination of \(\vec{D}\). The magnitude of \(\vec{w}\) is set to 2 rad/s, leading to the expression \(\vec{w} = \frac{2}{\sqrt{75}} (7\hat{i} - 5\hat{j} + \hat{k})\). Finally, the velocity \(\vec{v}\) of the head of vector \(\vec{C}\) is calculated using \(\vec{v} = \vec{w} \times \vec{C}\). The correctness of this approach is questioned, indicating a need for verification.
wizard85
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Angular velocity and vectors...

Homework Statement



Given the following vectors:

\vec A=\hat i +\hat j - 2\hat k and \vec C=\hat j - 5\hat k

Let \vec A and \vec C be drown from a common origin and let \vec C rotate about \vec A with angular velocity \vec w of 2 \frac{rad}{s}. Find the velocity \vec v of the head of \vec C.



Homework Equations





The Attempt at a Solution



My step-by-step way for resolving it, is:

1)I know that \vec v= w \times \vec C
2) By multiplying: \vec A \times \vec C I'll find a vector parallel to \vec w namely D
3) Now, \vec D= \vec A\times \vec C=(\hat i +\hat j - 2\hat k) \times (\hat j - 5\hat k) = 7*\hat i -5*\hat j +\hat k

4) I also know that \vec w is obtained by a linear combination of \vec D's parameter. Then:

\vec w= a * \vec D=a * (7*\hat i -5*\hat j +\hat k)

but |\vec w|= 2 so a= \frac{2}{|\vec D|} --> a=\sqrt{75}. Finally \vect w= \frac{2}{\sqrt{75}} (7*\hat i -5*\hat j +\hat k)

Thus:

\vect v= \vect w \times \vect C = \frac{2}{\sqrt{75}} (7*\hat i -5*\hat j +\hat k) \times (\hat j - 5\hat k)

is that correct?

Thanks to all... :smile:
 
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wizard85 said:

Homework Statement



Given the following vectors:

\vec A=\hat i +\hat j - 2\hat k and \vec C=\hat j - 5\hat k

Let \vec A and \vec C be drown from a common origin and let \vec C rotate about \vec A with angular velocity \vec w of 2 \frac{rad}{s}. Find the velocity \vec v of the head of \vec C.



Homework Equations





The Attempt at a Solution



My step-by-step way for resolving it, is:

1)I know that \vec v= w \times \vec C
2) By multiplying: \vec A \times \vec C I'll find a vector parallel to \vec w namely D
3) Now, \vec D= \vec A\times \vec C=(\hat i +\hat j - 2\hat k) \times (\hat j - 5\hat k) = 7*\hat i -5*\hat j +\hat k

4) I also know that \vec w is obtained by a linear combination of \vec D's parameter. Then:

\vec w= a * \vec D=a * (7*\hat i -5*\hat j +\hat k)

but |\vec w|= 2 so a= \frac{2}{|\vec D|} --> a=\sqrt{75}. Finally \vect w= \frac{2}{\sqrt{75}} (7*\hat i -5*\hat j +\hat k)

Thus:

\vect v= \vect w \times \vect C = \frac{2}{\sqrt{75}} (7*\hat i -5*\hat j +\hat k) \times (\hat j - 5\hat k)

is that correct?

Thanks to all... :smile:

nobody? :frown:
 
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