How Do You Derive the Kinematic Equation \(v_f^2 = v_i^2 + 2ad\)?

AI Thread Summary
To derive the kinematic equation \(v_f^2 = v_i^2 + 2ad\), one can start by using the equation \(v_f = v_i + at\) to solve for time \(t\) and then substitute this into the displacement equation \(d = v_i t + \frac{1}{2}at^2\). The initial confusion stemmed from misinterpreting "derive" as taking derivatives rather than using algebraic manipulation. After clarification, it was confirmed that using any kinematic equations is permissible for the derivation. The discussion concluded with the participant successfully understanding the correct approach to derive the equation.
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Homework Statement



Derive (v_f)^2 = (v_i)^2 +2ad


Homework Equations



(v_f)^2 = (v_i)^2 + 2ad
(v_f) = (v_i) + at
d = (v_i)t + \frac{1}{2}at^2


The Attempt at a Solution



I have attempted to replace the variables with others from other kinematic equations such as v_f = v_i + at. However, I am getting no where. I have also taken the derivative of the equation (or so I think) but if I have not done it correctly, then I am just going no where.

When taking the derivative of the equation (v_f^2 = v_i^2 + 2ad) I remembered dv/dt = a , a in this equation is constant, and dd/dt = v, thus I got 2a=2a+2v and once simplified brings me to 0=v? I feel I am deriving the equation incorrectly.

Now, after having exhausted my thoughts, I've come asking for help.
 
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Are you supposed to derive the equation from first principles? What i mean is are you allowed to use:

d = (v_i)t + \frac{1}{2}at^2
 
Yes. I can use any type of equation. And any principles. I'm just at a loss as to how to get started. I should be fine with a little nudge in the right direction.
 
Lego said:
Yes. I can use any type of equation. And any principles. I'm just at a loss as to how to get started. I should be fine with a little nudge in the right direction.

You can solve for t, in the equation vf = v0 + at... then substitute t into the d equation posted, that will give you the result.
 
learningphysics said:
You can solve for t, in the equation vf = v0 + at... then substitute t into the d equation posted, that will give you the result.

Thank you. I've got it now. I had returned to using the other equations, but the word "derive" kept making my brain do derivatives. I guess that's what I get for being a math minor and taking as few physics classes as possible.

Thank you, again.
 
Lego said:
Thank you. I've got it now. I had returned to using the other equations, but the word "derive" kept making my brain do derivatives. I guess that's what I get for being a math minor and taking as few physics classes as possible.

Thank you, again.

no prob.
 
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