How Do You Determine Moments of a 3D Model?

AI Thread Summary
To determine the moments of a 3D model, the equations for torque are established as Mx = Fz * ya, My = Fx * za, and Mz = -Fx * ya. The discussion emphasizes the importance of understanding the coordinate system and applying the left-hand rule for directionality. A suggestion is made to incorporate a second term in each equation to fully capture the torque calculations. Additionally, the concept of using the cross product of vectors in Cartesian coordinates is introduced as a potential method for finding the missing terms. Understanding these principles is crucial for accurately calculating moments in 3D models.
jeluu9
Messages
1
Reaction score
0

Homework Statement


(See pic attachment)

Homework Equations


Moment/Torque = Force * d (Force arm)

The Attempt at a Solution


I have so far
Mx = Fz * ya
My = Fx * za
Mz = -Fx * ya

How I got these answers is by looking at the cube from the component's axis and whether or not it produces a torque. I am following what I observed the professor doing but not sure about why or how one knows how to do this. Please help!

with the coordinate system being CCW is (+) and (+) xyz based on the "left-hand rule"
 

Attachments

  • Q_01.jpg
    Q_01.jpg
    14.4 KB · Views: 502
Physics news on Phys.org
Hi jeluu9. Welcome to Physics Forums!

There should be two terms in each of these equations, and you already have one of the terms written correctly. Try to figure out what the missing term in each equation is.

Have you learned yet about taking the cross product of two vectors, if the vectors are expressed in cartesian component form?

Chet
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top