How do you determine the function of a spring in terms of k?

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The discussion revolves around determining the function of a spring using Hooke's Law, specifically how to express the change in distance "y" in terms of the spring constant "k." The user calculates a change in "y" as -0.1 inches and attempts to derive a formula, but struggles with the second part of the question regarding expressing the relationship as a function of "k." There is confusion about the clarity of the problem, which is described as vague, particularly since it pertains to an introductory course on strength of materials rather than physics. The user seeks assistance in understanding how to relate their findings to the spring constant effectively. Overall, the thread highlights challenges in applying theoretical concepts to practical problems in engineering contexts.
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Homework Statement



*See Attachment*

The problem states to find "y" which I'm assuming is the change in distance from the original point marked "y".


Homework Equations


Hooke's Law


The Attempt at a Solution



I'm pretty sure the change in Y is -0.1in

P=-ky
y=p/-k
y=-0.1

I have no idea how to express things as a function of k (second part of the question)

Thanks!
 

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Maybe it's clear for others, but I find the question totally vague.
 
Yeah...that is why I'm quite confused. This isn't for physics either, this is "introductory" homework for strength of materials...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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