Engineering How Do You Determine Thevenin Equivalent Circuits and Maximize Power Transfer?

AI Thread Summary
To determine the Thevenin equivalent circuit, the first step is to find the open-circuit voltage (VOC), which was calculated correctly as 2.5V using mesh analysis. The confusion arose when attempting node voltage analysis, where the result was incorrect due to not accounting for the controlled source in the equations. The test source method was used to find the Thevenin resistance, yielding a value of 6 ohms after correcting the approach by removing the independent voltage source. It was noted that using a test voltage source versus a test current source can yield different insights, but both methods are valid. Understanding the proper setup for node voltage equations is crucial for accurate results in circuit analysis.
jdawg
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Homework Statement



Find the Thevenin equivalent circuit for the circuit shown. You will need to find VOC and then use the test source method to find the Thevenin resistance. Using the Thevenin equivalent circuit,determine the load resistor that results in maximum power transferred to that load resistor and the amount of that power.

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The Attempt at a Solution


(Fig.1)[/B]I'm a little stuck on this problem. I first used mesh analysis to find VOC, which came out correct: VOC=2.5V.
But I tried to do it with node voltage analysis as well to see if it would work also and it came out a little messed up:
(VA-5)/7 +VA/10=0
VA=2.94V
Is there a reason why node voltage doesn't work in this situation or am I just doing it wrong?
(Fig.2) I tried letting ITest=1A and used mesh analysis:
i2=ITest=1
0.2(V2)-(5ohm)(i1)+5v-(7ohm)(i1)-(10ohm)(i1-i2)=0
Substituted and did some algebra:
i1=0.705
I am super confused at this point :(
Is there an advantage to using a test voltage source vs using a test current source?
Should I have let VTest=2.5V instead?
 

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Oops I forgot to take out the independent voltage source for the test method! I let Vtest=2.5v and found Itest=0.467 so Rth=6ohms! I feel like I understand the test method now, could someone explain how I messed up with the node voltage equation in the Fig. 1 section?
 
jdawg said:
Oops I forgot to take out the independent voltage source for the test method! I let Vtest=2.5v and found Itest=0.467 so Rth=6ohms! I feel like I understand the test method now, could someone explain how I messed up with the node voltage equation in the Fig. 1 section?
You didn't account for the controlled source in the node equation. You need all sources active if you want to find the open circuit voltage.
 
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