How Does Acceleration Affect Pendulum Frequency?

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    Pendulum Physics
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The discussion focuses on the effect of acceleration on pendulum frequency, illustrated through an experiment with a pendulum suspended from keys. Initially, the pendulum completes 90 cycles in one minute, and during the plane's acceleration, it completes 97 cycles. The participant attempts to calculate the plane's acceleration using the formulas for pendulum period and frequency but initially arrives at an incorrect value of 1.58. After considering the vector nature of gravitational acceleration and the plane's acceleration, the correct calculation yields an acceleration of 5.8. The discussion highlights the importance of vector addition in solving physics problems related to pendulum motion.
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Homework Statement


While waiting for your plane to take off, you suspend your keys from a thread and set the resulting pendulum oscillating. It completes exactly 90 cycles in 1 minute. You repeat the experiment as the plane accelerates down the runway, and now find the pendulum completes exactly 97 cycles in 1 minute.

Find the plane's acceleration.

Homework Equations


T = 2 pi sqrt(L/g)
T = 1 / freq.

The Attempt at a Solution


T1 = 2 pi sqrt(L/g)
(T1 / (2 pi))2 g = L

T2 = 2 pi sqrt(L/(g + a))
a = L / (T2 / (2 pi))2 - g
a = (T1 / (2 pi))2 g / (T2 / (2 pi))2 - g

I get that a = 1.58, but that's wrong. The right answer is 5.8. What did I do incorrectly?
 
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Think of g and a as vectors. What directions do they point in? What's the correct way to add vectors that point in those directions?
 
sqrt(g^2 + a^2)?
 
Wow. That does give me the right answer. Thanks a lot. :)
 
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