How Far Behind a Mirror Is an Image Created by a Flat Mirror?

Thread starter kill00
Start date Apr 3, 2011
Tags

Law Law of reflection Light Reflection Reflection of light

AI Thread Summary

The image created by a flat mirror is located at the same distance behind the mirror as the object is in front of it. This means if an object is 5 feet away from the mirror, the image appears to be 5 feet behind the mirror. The image is referred to as a virtual image because it cannot be projected onto a screen; it only appears to exist behind the mirror. The discussion highlights the straightforward nature of reflections in flat mirrors and the concept of virtual images. Understanding these principles is essential for grasping basic optics.

Apr 3, 2011

kill00

Homework Statement

How far behind the mirror is the image of an object that is located in front of a flat (plane) mirror?

Why do you think the image produced by a flat (plane) mirror is called a virtual image

Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Apr 3, 2011

kill00

Nvm, I got it.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Understanding Forces and their Vector Components'

I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?

View full post »