How Many coulombs pass through each resistor in a circuit?

AI Thread Summary
In a circuit with a 12-volt battery and two ohm resistors in series, the relationship between voltage, current, and resistance is defined by Ohm's Law (V=IR). To find the current, the total resistance must be calculated, which is 2 ohms in this case. The current can then be determined using the formula I = V/R, resulting in a current of 6 amps. Since 1 coulomb is equivalent to the charge that passes through a point in a circuit in one second when a current of 1 ampere flows, 6 coulombs will pass through each resistor in one second. Understanding these concepts is essential for solving electric circuit problems effectively.
Precut
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Homework Statement


My question relating to physics and electric circuits, is "If a circuit consists of a 12 volt battery and two ohm resistors connected in series, then how many Coulombs pass through each resistor in a second".

Thank you all so very much.

Homework Equations


V=IR

The Attempt at a Solution


I tried using things such as "1 coulomb=6.25 x 10^18 to solve the problems but I just don't know how to.
 
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What do V, I, and R in Ohm's law stand for? How are coulombs related to Ohm's law?
 
Drakkith said:
What do V, I, and R in Ohm's law stand for? How are coulombs related to Ohm's law?
Volts=Current x Resistance
 
Precut said:
Volts=Current x Resistance
What's the definition of 'current'? How is it measured? What are its units?
 
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