How Many Excess Electrons or Protons Does a Suspended Water Drop Have?

AI Thread Summary
To determine the number of excess electrons or protons on a suspended water drop in an electric field, the forces must balance: the gravitational force (Fg = mg) equals the electric force (F = E*q). Given the mass of the water drop (3.99 x 10^-9 kg) and the electric field strength (10,800 N/C), the net charge (q) on the drop can be calculated. The charge of a single electron or proton is known, allowing for the conversion of net charge into the number of excess particles. Ultimately, the calculation reveals how many excess electrons or protons are present on the water drop.
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Homework Statement


A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 10800 N/C. The mass of the water drop is 3.99 x 10-9 kg. How many excess electrons or protons reside on the drop?


Homework Equations


which equation do i use? Do i need to use the mass of a proton to find the number of excess protons?


The Attempt at a Solution



F=ma; E=F/q
 
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The force from gravity acting on the rain drop, Fg=mg, will need to equal the force from the electric field, F=E*q, for the drop to stay motionless
 
And how do I solve for how much protons are present?
 
(Or electrons)

Well you're going to solve for q, so you'll know the NET charge on the raindrop. You know the charge of a SINGLE proton or electron
 
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