How to Calculate Voltage Gain for Amplifiers B and D with Limited Input Voltage

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The discussion focuses on calculating the voltage gain for amplifiers B and D, given a limited input voltage of ±600mV. The initial attempt to find the gain for amplifier B yielded a value of 8.33, but further analysis revealed discrepancies in the output voltage interpretation. Participants noted that the output voltage appears to be around 5.0V for an input of approximately 0.55V, suggesting a gain closer to 9.09. The original poster later confirmed that with proper graphing techniques, they were able to arrive at the correct answer. Accurate interpretation of the amplifier's characteristics is crucial for determining voltage gain effectively.
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Homework Statement



"The graph shows the characteristics of four different voltage amplifiers (A-D). The input voltage to these amplifiers is limited to between + & - 600mV.

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If you cannot see it properly it also says "If the input voltage is as shown (see bottom graph), sketch the output voltage for amplifiers B and D."

Homework Equations



Voltage gain = change in output voltage divided by change in input voltage.



The Attempt at a Solution



To use B as an example. I've tried finding the voltage gain (rise over run or the formula above) to get 8.33. I then use that as the voltage gain and rearrange the above formula but alas it didn't work. If it helps, the book shows (for B) a peak voltage of 1.8v and a trough of 1.8v.

Any help would be appreciated.
 
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breeno said:
To use B as an example. I've tried finding the voltage gain (rise over run or the formula above) to get 8.33. I then use that as the voltage gain and rearrange the above formula but alas it didn't work. If it helps, the book shows (for B) a peak voltage of 1.8v and a trough of 1.8v.

For B, your rise over the run approach is the way to go. :approve: But you might want to redo the math. :frown: The way I see the figure (which isn't too easy, it's kind of squashed), the output voltages seems to around 5.0 V for an input voltage of around 0.55 V. That doesn't give a gain of 8.33.
 
collinsmark said:
For B, your rise over the run approach is the way to go. :approve: But you might want to redo the math. :frown: The way I see the figure (which isn't too easy, it's kind of squashed), the output voltages seems to around 5.0 V for an input voltage of around 0.55 V. That doesn't give a gain of 8.33.

It's 5v and 0.6v. :p

5/0.6 = 8.33.
 
breeno said:
It's 5v and 0.6v. :p

5/0.6 = 8.33.

Yeah, it's kind of hard for me to see because the figure is squished up. On the other hand, if you use 5/0.55 = 9.09, you'll get the answer in the book. I'm not sure if the book made a mistake in the figure, or the answer, or if it's just because I just can't interpret the figure very well myself.
 
collinsmark said:
Yeah, it's kind of hard for me to see because the figure is squished up. On the other hand, if you use 5/0.55 = 9.09, you'll get the answer in the book. I'm not sure if the book made a mistake in the figure, or the answer, or if it's just because I just can't interpret the figure very well myself.

Thanks for your help.

I went through with a tutor today and it turns out my system was right in the way of getting it and on an exam I will get a 10% range for graph style questions. I re-drew the graph on graph paper and ended up getting the correct answer.

Thanks for helping!
 
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