How to Derive the Electric Field Outside a Charged Spherical Conductor?

Foxx
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What is your question? You basically would have, i believe, two types of questions related to electric field and a sphere. When the charge is all on the surface of a sphere or when it is uniformly distributed. Usually Gauss law is used in both cases, basically you youse this law for all gaussian surfaces, because it takes advantage of symmetrical shapes, such as a sphere in this case.
 
txs, for replying stupidmath. My question is if the electric potential inside a charged spherical conductor of radius R is given by V = keQ/R, and the potential outside is given by V = keQ/r. Using Er = -dV/dr, how would I derive the electric field outside this charge distribution?
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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