How to express ωₙ in terms of only mass (m) and stiffness (k)?

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To express the natural frequency ωₙ in terms of mass (m) and stiffness (k), one approach involves using Newton's laws and free body diagrams for each mass in a pulley system. The discussion highlights the importance of understanding the initial displacement, denoted as δₛₜ, and how it relates to the system's dynamics. A simpler method suggested is to utilize energy methods by introducing a generalized coordinate x to derive kinetic and potential energies. The natural frequency can be determined from the total energy equation, leading to the relationship ω² = k/μ, where μ represents the effective mass. Ultimately, both force equations and energy conservation can be employed to derive the desired expression for ωₙ.
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Summary: How to express ωₙ in terms of only mass (m) and stiffness (k)? I tried doing it with F=kx but it is out of my ability to simplify it to only m and k.

Screenshot 2022-05-17 155003.png


Here is my approach:
Screenshot 2022-05-17 175502.png
 
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Tell me what is ##\delta_{st}##?
You need (a free body diagram and) Newton's law for each mass, and the constraint on the positions (and hence accelerations) engendered by the pulley system.
 
hutchphd said:
Tell me what is ##\delta_{st}##?
You need (a free body diagram and) Newton's law for each mass, and the constraint on the positions (and hence accelerations) engendered by the pulley system.
From what i was taught in my lecture classes, ##\delta_{st}## means the initial displacement that the spring has before we displace it further by x. I am not sure if it is needed in this case.

Is my free body diagram correct for the 2 identical masses?
Screenshot 2022-05-17 194156.png
 
Although you can solve this by finding the force equations and considering the tension in the string etc, there is a much simpler way by using energy methods if you can manage to introduce a generalised coordinate ##x## that describes the position of the system and write down the kinetic and potential energies as depending on ##x##. Generally, if the total energy is on the form ##E = (\mu \dot x^2 + k (x-a)^2)/2 + C##, where ##C##, ##\mu##, ##k##, and ##a## are constants, then the natural frequency is given by ##\omega^2 = k/\mu##.
 
Good. Write Newton's Law for body 1 and for body 2 (along the direction of travel for each). Eliminate T. Use constraint to eliminate coordinate 1 (or 2 if you prefer). Choose ##\delta_{st}## to give the correct static limit.
This should now look like an oscillator diff. equation.
Perhaps you can use energy conservation to get to the same answer more easilly, but you should be able to do either, I reckon.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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