How to find the distance of this vector? did i draw it right?>

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The vector drawing is incorrect as line L should be perpendicular to line a and pass through point b. To determine the coordinates of point P, one can write the equations for both lines and calculate their intersection. This method ensures accurate positioning of point P relative to the defined lines. Clarification on the drawing and calculations is essential for correct vector analysis. Accurate representation and mathematical formulation are key to solving the problem effectively.
mr_coffee
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Hello everyone, I'm not sure if i drew this right...I'm also confused on how I'm suppose to determine the coordinates of P. Thanks!

Here is the picture and directions:
http://img204.imageshack.us/img204/7265/ex36nk.jpg
 
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No, it's not drawn correctly. The line L must be perpendicular to line a, yet pass through point b.

One way to find the coordinates of point P is to write the equations of the two lines and find where they intersect.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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