How to Find Thevenin and Norton Equivalents with Central Power Source?

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To find the Thevenin and Norton equivalents with a central power source, it's important to recognize that the position of the power source does not affect the overall circuit behavior. The circuit can be simplified by exchanging the positions of components, such as moving the 20-ohm resistor and the 4-amp current source, while maintaining the same nodal points. This transformation is valid because the components remain in parallel, preserving the circuit's characteristics. Understanding these principles can help in solving similar problems effectively. The discussion emphasizes the importance of recognizing equivalent circuit configurations for analysis.
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Thevenin/Norton Equivalent,PLEASE HELP!

Hi I apolgise for posting a question which is rather simple but I am struggling to grasp the concept of it,ive done many questions like this before,but this one in particular throws me because the power source is always on the left hand side of the circuit,but in this case its in the middle
Any help would be appreciated,this question has to be done by tomorrow so any replies i will be really grateful,thanks

Question
Find the Thevenin and Norton Equivalent circuits for the circuit shown in the picture
the resistors values are in ohms


Thanks for your time
 

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Exchange the positions of the 20 ohm resistor and the 4 amp current source. The circuit behavior will be the same but the source will be on the left hand side.
 


Thanks very much for the reply
 


The Electrician said:
Exchange the positions of the 20 ohm resistor and the 4 amp current source. The circuit behavior will be the same but the source will be on the left hand side.

is it valid to do that, i do see the circuit is unchanged.
 
seto6 said:
is it valid to do that, i do see the circuit is unchanged.

It is valid since the two share the same two nodal points before and afterwards (i.e. they're still in parallel)
 

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