Engineering How to find voltage in an open circuit

AI Thread Summary
To find the voltage in an open circuit, it is essential to recognize that no current flows through resistors R2 and R3, resulting in zero voltage drop across them. When the output is unconnected, the voltage across the open circuit (Voc) is equal to the voltage of the source, which in this case is 5V. The approach of using a voltage divider is not applicable since there are no resistors connected in the output path. The discussion confirms that the open-circuit voltage is indeed 5V. Additionally, the conversation shifts to exploring the short-circuit current.
tooperoo
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Homework Statement



Hi guys, attached is a photo of the circuit. Apologies for the bad drawing, but paint is hard :P

What I am wondering is, how do you find the voltage of the open circuit with circuits like these? I have used Thevenin and Norton equivalent circuits before, but the circuits didn't look like this. Any guidance is appreciated! Thank you


Homework Equations





The Attempt at a Solution

 

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With an open circuit, how much current is flowing through R2 and R3 ? What is the voltage across them?
 
There isn't any at all, right?

What i usually do for the Voc is combine the resistors with a voltage divider and then multiply it by the voltage source. But u thought you need at least two resistors to do that approach.
 
You don't have a voltage divider in the circuit when the output is unconnected.

Look at it this way... If there is no current flowing through R2 and R3 the voltage drop across R2 and across R3 is zero. You can remove and replace R2 and R3 with wire.
 
So say if the voltage source was pumping out 5v, the Voc would be 5v?
 
tooperoo said:
So say if the voltage source was pumping out 5v, the Voc would be 5v?

Are you asking or telling?
 
Hahaha definitely asking. I'm nearly positive it would be 5v but I want to check if I'm correct.
 
tooperoo said:
Hahaha definitely asking. I'm nearly positive it would be 5v but I want to check if I'm correct.
That's the open-circuit voltage. Now what is the short-circuit current?
 

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