How to find voltage in an open circuit

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SUMMARY

The voltage in an open circuit can be determined using the open-circuit voltage (Voc) concept. In the discussed circuit, with a voltage source of 5V and no current flowing through resistors R2 and R3, the Voc is confirmed to be 5V. The absence of current results in zero voltage drop across R2 and R3, allowing them to be replaced with a wire in the analysis. This approach clarifies the relationship between the voltage source and the open-circuit voltage.

PREREQUISITES
  • Understanding of open-circuit voltage (Voc)
  • Familiarity with Thevenin and Norton equivalent circuits
  • Basic knowledge of voltage dividers
  • Concept of current flow in electrical circuits
NEXT STEPS
  • Study Thevenin's theorem in depth
  • Learn about short-circuit current analysis
  • Explore voltage divider rule applications in various circuits
  • Investigate practical applications of open-circuit voltage in real-world scenarios
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in understanding open-circuit voltage and its implications in circuit analysis.

tooperoo
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Homework Statement



Hi guys, attached is a photo of the circuit. Apologies for the bad drawing, but paint is hard :P

What I am wondering is, how do you find the voltage of the open circuit with circuits like these? I have used Thevenin and Norton equivalent circuits before, but the circuits didn't look like this. Any guidance is appreciated! Thank you


Homework Equations





The Attempt at a Solution

 

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With an open circuit, how much current is flowing through R2 and R3 ? What is the voltage across them?
 
There isn't any at all, right?

What i usually do for the Voc is combine the resistors with a voltage divider and then multiply it by the voltage source. But u thought you need at least two resistors to do that approach.
 
You don't have a voltage divider in the circuit when the output is unconnected.

Look at it this way... If there is no current flowing through R2 and R3 the voltage drop across R2 and across R3 is zero. You can remove and replace R2 and R3 with wire.
 
So say if the voltage source was pumping out 5v, the Voc would be 5v?
 
tooperoo said:
So say if the voltage source was pumping out 5v, the Voc would be 5v?

Are you asking or telling?
 
Hahaha definitely asking. I'm nearly positive it would be 5v but I want to check if I'm correct.
 
tooperoo said:
Hahaha definitely asking. I'm nearly positive it would be 5v but I want to check if I'm correct.
That's the open-circuit voltage. Now what is the short-circuit current?
 

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